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0.3x^2-0.2x=0.3
We move all terms to the left:
0.3x^2-0.2x-(0.3)=0
We add all the numbers together, and all the variables
0.3x^2-0.2x-0.3=0
a = 0.3; b = -0.2; c = -0.3;
Δ = b2-4ac
Δ = -0.22-4·0.3·(-0.3)
Δ = 0.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.2)-\sqrt{0.4}}{2*0.3}=\frac{0.2-\sqrt{0.4}}{0.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.2)+\sqrt{0.4}}{2*0.3}=\frac{0.2+\sqrt{0.4}}{0.6} $
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